![American engineer and railroad journal . Example No. 2 .• Given the radius of the main trackR = 573.69, the radius of the turnout curve, R = 380, thestandard gauge g— American engineer and railroad journal . Example No. 2 .• Given the radius of the main trackR = 573.69, the radius of the turnout curve, R = 380, thestandard gauge g—](https://c8.alamy.com/comp/2CH5KKW/american-engineer-and-railroad-journal-example-no-2-given-the-radius-of-the-main-trackr-=-57369-the-radius-of-the-turnout-curve-r-=-380-thestandard-gauge-g-5-ft-6-in-and-the-narrow-gauge-the-radius-of-the-turnout-=-a-the-standard-gauge-=-gand-the-narrow-gauge-=-g-in-the-triangle-c-there-are-given-the-side-c-=-=-3-ft-6-in-to-find-the-frog-angle-d-1-e-=-b-a-cfig-13-57369-38o573-69-2-75-380275-3o-j-2-s-r-i-g-=-i-00-00000000-s-r-ig-g-=-193-69-22848592-r-i-g-g-379-5-ar-comp-74210744-r-i-g-=-570-94-ar-2CH5KKW.jpg)
American engineer and railroad journal . Example No. 2 .• Given the radius of the main trackR = 573.69, the radius of the turnout curve, R = 380, thestandard gauge g—
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